It is given that the equation x^2 - px + q = 0 has roots p and q. We can begin solving either by using the sum and product formulae, or by simply substituting the roots into the equation and then work with the resultant equations. Either way, the approach is more or less the same because the Sum and Product of roots formulae are nothing but derivations made by substituting roots into the equation for the standard equation.
Here,
Sum of roots = p
=> p + q = p
=> q = 0
Product of roots = q
=> pq = q
=> pq - q = 0
=> q (p - 1) = 0
=> q = 0, p = 1
The values of p and q hence found are p = 1, and q = 0. This makes the original equation x^2 - x = 0.
Here,
Sum of roots = p
=> p + q = p
=> q = 0
Product of roots = q
=> pq = q
=> pq - q = 0
=> q (p - 1) = 0
=> q = 0, p = 1
The values of p and q hence found are p = 1, and q = 0. This makes the original equation x^2 - x = 0.
if a and b are roots of x^2-px+q=0 , then find Σ(a^2)...?
ReplyDeleteIf p and q are the roots of the equation x^2+2x+1=0, find p^3+q^3
ReplyDelete3
DeleteP and q r nonzero constants the equation x^2+px+q =0 has roots alpha n beta then the equation qx^2+px+1=0 has ropts
ReplyDeleteIf p and q are the roots of the equation x^2+k+1=0.Then 1/p+1/q=?
ReplyDeleteSum of roots = p
Deletep+q=p
q=0
Product of roots = q
p.q = q
pq-q=0
q(p-1)=0
q=0,p-1=0
q=0,p=1
Therefore according to the question
1/p+1/q
1/2/0=1/2×1/0
Is NOT DEFINED
If p and q are the roots of 9x^2-5x+4, then find p^2+q^2.
ReplyDeleteIf p and q are the roots of a quadratic equation , find the equation
ReplyDeleteIf p and q are roots if the equation x^2-px+q then find the value of p and q ?
ReplyDeleteBe sale etna bhi nahiata
DeleteSir/madam
ReplyDeleteThis is done very correctly and I got the same answer...But in the rd sharma text the options are different. It might be some printing mistake right